35x^2+108x+28=0

Solution for 35x^2+108x+28=0 equation:

35x^2+108x+28=0

a = 35; b = 108; c = +28;
Δ = b2-4ac
Δ = 1082-4·35·28
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7744}=88$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(108)-88}{2*35}=\frac{-196}{70}
=-2+4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(108)+88}{2*35}=\frac{-20}{70}
=-2/7
$